5.3 The Fundamental Theorem of Calculus/9: Difference between revisions
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<math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt | <math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt</math><br> | ||
= 1\cdot(y^{2}sin{(y)})-0\cdot(2^{2}sin{(2)}) | = 1\cdot(y^{2}sin{(y)})-0\cdot(2^{2}sin{(2)}) | ||
= y^{2} sin{(y)} | = y^{2} sin{(y)} | ||
</math> | </math> | ||
Revision as of 02:32, 26 August 2022
= 1\cdot(y^{2}sin{(y)})-0\cdot(2^{2}sin{(2)})
= y^{2} sin{(y)}
</math>
