6.2 Trigonometric Functions: Unit Circle Approach/53: Difference between revisions

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\tan{\left(\frac{8\pi}{3}\right)} &= \frac{\frac{\sqrt{3}}{2}}{-\frac{{1}}{2}} = \left(2\right) = \frac{\sqrt{3}}{-1} = -\sqrt{3}  
\tan{\left(\frac{8\pi}{3}\right)} &= \frac{\frac{\sqrt{3}}{2}}{-\frac{{1}}{2}} = \left(2\right) = \frac{\sqrt{3}}{-1} = -\sqrt{3}  


& \cot{\left(\frac{8\pi}{3}\right)} &= \frac{-\frac{1}{2}} {\frac{\sqrt{3}}{2}} \cdot 2 = \frac{-1}{\sqrt{3}} \cdot \sqrt{3}=  \\[2ex]  \end{align} </math>
& \cot{\left(\frac{8\pi}{3}\right)} &= \frac{-\frac{1}{2}} {\frac{\sqrt{3}}{2}} \cdot 2 = \frac{-1}{\sqrt{3}} \cdot \sqrt{3}= \frac{-\sqrt{3}}{3} \\[2ex]  \end{align} </math>

Revision as of 04:09, 26 August 2022