5.3 The Fundamental Theorem of Calculus/28: Difference between revisions
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&= \left[3(1)+\frac{2(1)^{5/2}}{5}\right]-\left[3(0)+\frac{2(0)^{5/2}}{5}\right] \\[2ex] | &= \left[3(1)+\frac{2(1)^{5/2}}{5}\right]-\left[3(0)+\frac{2(0)^{5/2}}{5}\right] \\[2ex] | ||
&= 3+\frac{2}{5} = \frac{15}{5}+\frac{2}{5} = \frac{17}{ | &= 3+\frac{2}{5} = \frac{15}{5}+\frac{2}{5} = \frac{17}{6} | ||
\end{align} | \end{align} | ||
</math> | </math> |
Revision as of 04:20, 26 August 2022