5.3 The Fundamental Theorem of Calculus/9: Difference between revisions
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<math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt</math><br> | <math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt</math><br> | ||
<math>1\cdot(y^{2} | <math>1\cdot(y^{2}\cdotsin{(y)})-0\cdot(2^{2}sin{(2)})= | ||
y^{2} sin{(y)}</math> | y^{2} sin{(y)}</math> | ||
Revision as of 16:18, 26 August 2022
Failed to parse (unknown function "\cdotsin"): {\displaystyle 1\cdot(y^{2}\cdotsin{(y)})-0\cdot(2^{2}sin{(2)})= y^{2} sin{(y)}}
