6.2 Trigonometric Functions: Unit Circle Approach/98: Difference between revisions

Revision as of 17:16, 26 August 2022

$f(\theta )=\sin(\theta )$
$g(\theta )=\cos {(\theta )}$
$\theta =60^{\circ }$

$g\left({\frac {\theta }{2}}\right)=g\left({\frac {60^{\circ }}{2}}\right)=g(30^{\circ })=\cos(60^{\circ })={\frac {1}{2}}$

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	<math> \theta = 60^{\circ}</math> <br><br>		<math> \theta = 60^{\circ}</math> <br><br>

	<math> g\left(\frac{\theta}{2}\right)=g\left(\frac{60^{\circ}}{2}\right) = g(30^{\circ})</math>		<math> g\left(\frac{\theta}{2}\right)=g\left(\frac{60^{\circ}}{2}\right) = g(30^{\circ}) = \cos(60^{\circ}) = \frac{1}{2}</math>