5.3 The Fundamental Theorem of Calculus/33: Difference between revisions

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<math>\int_{1}^{2}\left(1+2y^2\right)dy</math>  
<math>\int_{1}^{2}\left(1+2y^2\right)dy</math>  
=<math>\int_{1}^{2}\left(4y^2+4y+1\right)dy</math>
=<math>\int_{1}^{2}\left(4y^2+4y+1\right)dy</math>
=<math>\frac{4y^3}{3}+frac{4y^2}{2}</math>
=<math>\frac{4y^3}{3}+ frac{4y^2}{2}</math>

Revision as of 18:50, 26 August 2022

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