5.5 The Substitution Rule/54

$\int _{0}^{7}{\sqrt {4+3x}}\,dx$

${\begin{aligned}u&=4+3x\\[2ex]du&=3\,dx\\[2ex]\end{aligned}}$

${\begin{aligned}\int {\frac {\sin {(\ln {(x))}}}{x}}dx&=\int {\frac {1}{x}}\sin(\ln {(x)})dx=\int \left({\frac {1}{x}}dx\right)\sin {(\ln {(x)})}\\[2ex]&=\int (du)\sin {(u)}=\int \sin {(u)}du\\[2ex]&=-\cos {(u)}+C\\[2ex]&=-\cos {(\ln {(x)})}+C\end{aligned}}$