5.4 Indefinite Integrals and the Net Change Theorem/21: Difference between revisions

Revision as of 19:13, 30 August 2022

$\int _{0}^{2}(6x^{2}-4x+5)dx$ = ${\frac {6x^{2+1}}{2+1}}-{\frac {4x^{1+2}}{1+2}}+{5x}{\bigg |}_{0}^{2}$

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	<math>\int_{0}^{2}(6x^{2}-4x+5) dx</math> = \frac{6x^{2+1}}{2+1}-\frac{4x^{1+2}}{1+2}+{5x}\bigg\|_{0}^{2}		<math>\int_{0}^{2}(6x^{2}-4x+5) dx</math> = <math>\frac{6x^{2+1}}{2+1}-\frac{4x^{1+2}}{1+2}+{5x}\bigg\|_{0}^{2}</math>