5.5 The Substitution Rule/69: Difference between revisions

Revision as of 15:44, 6 September 2022

${\begin{aligned}\int _{0}^{1}\left({\frac {e^{z}+z}{e^{z}+1}}\right)&=\int _{0}^{1}\end{aligned}}$

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 <math>
 \begin{align}
-\int_{e}^{e^4} \left(\frac{dx}{x\sqrt{\ln(x)}}\right) &= \int_{e}^{e^4} \left(\frac{1}{x} /frac{1}{\sqrt(\ln(x))}\right) dx
+\int_{0}^{1} \left(\frac{e^z + z}{e^z + 1}\right) &= \int_{0}^{1}
 \end{align}
 </math>