5.5 The Substitution Rule/69: Difference between revisions
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\begin{align} | \begin{align} | ||
\int_{0}^{1} \left(\frac{e^z + 1}{e^z + z}\right) &= \int_{}^{} \left((e^z +1) (\frac{1}{e^z +z}) \right) | \int_{0}^{1} \left(\frac{e^z + 1}{e^z + z}\right) &= \int_{}^{} \left((e^z +1) (\frac{1}{e^z +z}) \right) | ||
u= e^z + z | u= e^z + z | ||
Revision as of 15:47, 6 September 2022
