5.3 The Fundamental Theorem of Calculus/9: Difference between revisions

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<math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt</math><br>
<math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt</math><br><br>
 
<math>
 
\frac{d}{dy}\left[g(y)\right] = \frac{d}{dy}\left[\int_{2}^{y}t^2\sin{(t)}dt\right]
 
<math>= 1\cdot(y^{2}sin{(y)})-0\cdot(2^{2}sin{(2)})</math><br>
<math>= 1\cdot(y^{2}sin{(y)})-0\cdot(2^{2}sin{(2)})</math><br>
<math>= y^{2} sin{(y)}</math>
<math>= y^{2} sin{(y)}</math>

Revision as of 19:52, 6 September 2022