5.5 The Substitution Rule/41: Difference between revisions

Revision as of 09:03, 7 September 2022

$\int {\frac {1}{\sqrt {1-x^{2}}}}=\int {\frac {1}{u}}du=\ln u+c=\sin ^{(}-1){x}$

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 <math>
-\int \frac{1}{\sqrt{1-x^{2}}} = \int \frac{1}{u} du = \ln u +c = \sin^-1 {x}
+\int \frac{1}{\sqrt{1-x^{2}}} = \int \frac{1}{u} du = \ln u +c = \sin^(-1) {x}
 </math>