5.5 The Substitution Rule/41: Difference between revisions

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<math>
<math>


\int \frac{1}{\sqrt{1-x^{2}}} = \int \frac{1}{u} du = \ln u +c = \sin^(-1) {x}
\int \frac{1}{\sqrt{1-x^{2}}} = \int \frac{1}{u} du = \ln u +c = \sin^-^1 {x}
</math>
</math>

Revision as of 09:04, 7 September 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. TeX parse error: Double exponent: use braces to clarify"): {\displaystyle \int {\frac {1}{\sqrt {1-x^{2}}}}=\int {\frac {1}{u}}du=\ln u+c=\sin ^{-}^{1}{x}}