5.5 The Substitution Rule/21: Difference between revisions

From Burton Tech. Points Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 7: Line 7:
\begin{align}
\begin{align}


u &= \sqrt{u}
u &= \sqrt{u} \\[2ex]
  \\[2ex]
du &= \frac{1}{2}\ \frac{1}{\sqrt{t}} dx \\[2ex]
du &= \frac{1}{2}\ \frac{1}{\sqrt{t}} dx \\[2ex]
2du &= \frac{1}{\sqrt{t}} dx
2du &= \frac{1}{\sqrt{t}} dx
\end{align}
\end{align}
</math>
</math>

Revision as of 15:36, 7 September 2022