5.5 The Substitution Rule/7: Difference between revisions

Revision as of 16:47, 7 September 2022

Failed to parse (unknown function "\xsin"): {\displaystyle \int\xsin(x^{2})dx }

${\begin{aligned}u&=x^{2}\\[2ex]du&=2xdx\\[2ex]{\frac {1}{2}}du=dx\end{aligned}}$

Failed to parse (unknown function "\xsin"): {\displaystyle \begin{align} \int\xsin(x^{2})dx &= \end{align} }

@@ Line 1: / Line 1: @@
+<math>
+\int\xsin(x^{2})dx
+</math>
 <math>
 \begin{align}
+u &=x^{2} \\[2ex]
+du &=2xdx \\[2ex]
+\frac{1}{2}du=dx
-& \int{x\cdot sin{(x^2)}} dx \\[2ex]
+\end{align}
+</math>
-& \int \cfrac{sin(t)}{2} dt \\[2ex]
-& \cfrac{1}{2} \cdot \int{sin(t)} dt \\[2ex]
-& \cfrac{1}{2} \cdot (cos(x^2)) \\[2ex]
-&= -\cfrac{cos(x^2)}{2} +C
+<math>
+\begin{align}
+\int\xsin(x^{2})dx &=
 \end{align}
 </math>