6.5 Average Value of a Function/2: Difference between revisions

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&= \frac{1}{2\pi}\int_{-4\pi}^{4\pi}\sin{(u)}\left(\frac{1}{4}\,du\right) = \frac{1}{8\pi}\int_{-4\pi}^{4\pi}\sin(u)\,du \\[2ex]
&= \frac{1}{2\pi}\int_{-4\pi}^{4\pi}\sin{(u)}\left(\frac{1}{4}\,du\right) = \frac{1}{8\pi}\int_{-4\pi}^{4\pi}\sin(u)\,du \\[2ex]


&= -\frac{1}{8\pi}\cos(u)\bigg|_{-4\pi}^{4\pi} = \\[2ex]
&= -\frac{1}{8\pi}\cos(u)\bigg|_{-4\pi}^{4\pi} \\[2ex]


&= \left[-\frac{1}{8\pi}\cos(4\pi)\right]-\left[-\frac{1}{8\pi}\cos(-4\pi)\right] = \left[-\frac{1}{8\pi}(1)\right]+\left[\frac{1}{8\pi}(1)\right] \\[2ex]
&= \left[-\frac{1}{8\pi}\cos(4\pi)\right]-\left[-\frac{1}{8\pi}\cos(-4\pi)\right] = \left[-\frac{1}{8\pi}(1)\right]+\left[\frac{1}{8\pi}(1)\right] \\[2ex]

Revision as of 18:04, 7 September 2022




New upper limit:
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