6.2 Volumes/25: Difference between revisions

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&= \pi\left[\frac{2y^3}{3}-\frac{y^5}{5}\right]\Bigg|_0^1 \\[2ex]
&= \pi\left[\frac{2y^3}{3}-\frac{y^5}{5}\right]\Bigg|_0^1 \\[2ex]
&= \pi\left[\frac{2}{3}-\frac{1}{5}\right]= \\[2ex]
&= \pi\left[\frac{2}{3}-\frac{1}{5}\right]= \pi\left[\frac{10}{15}-\frac{3}{15}\right] \\[2ex]
 
&= \frac{7\pi}{15}
\pi\left[\frac{10}{15}-\frac{3}{15}\right] = \frac{7\pi}{15}


\end{align}
\end{align}
</math>
</math>

Revision as of 02:56, 12 September 2022