5.5 The Substitution Rule/21: Difference between revisions

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u &= \sqrt{t} \\[2ex]
u &= \sqrt{t} \\[2ex]
du &= \frac{1}{2}\ \frac{1}{\sqrt{t}} dx \\[2ex]
du &= \frac{1}{2}\ \frac{1}{\sqrt{t}} dt \\[2ex]
2du &= \frac{1}{\sqrt{t}} dx
2du &= \frac{1}{\sqrt{t}} dt
\end{align}
\end{align}
</math>
</math>

Revision as of 23:17, 13 September 2022