5.5 The Substitution Rule/37: Difference between revisions

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&= \int \frac{1}{{u}}(du) \\[2ex]
&= \int \frac{1}{{u}}(du) \\[2ex]
\text{Note: } \int \frac{1}{{x}}\;dx= \ln(x)+C \\[2ex]
&= \left| \ln(u) \right| + C \\[2ex]
&= \left| \ln(u) \right| + C \\[2ex]
&= \left| \ln(\sin(x)) \right| + C \\[2ex]
&= \left| \ln(\sin(x)) \right| + C \\[2ex]

Latest revision as of 19:18, 20 September 2022