5.4 Indefinite Integrals and the Net Change Theorem/23: Difference between revisions

Revision as of 14:56, 21 September 2022

$\int _{-1}^{0}(2x-e^{x})dx={\frac {2x^{2}}{2}}-e^{x}{\bigg |}_{-1}^{0}=-1-(1-{\frac {1}{e}})={\frac {1}{e}}-2$

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 <math>
-\int_{-1}^{0}(2x-e^x)dx =-1-(1-\frac{1}{e})=\frac{1}{e}-2
+\int_{-1}^{0}(2x-e^x)dx =\frac{2x^2}{2}-e^x\bigg|_{-1}^{0} = -1-(1-\frac{1}{e})=\frac{1}{e}-2
 </math>