5.4 Indefinite Integrals and the Net Change Theorem/29: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 1: | Line 1: | ||
<math> | <math> | ||
\int_{2}^{-1}\left(4y^3+\frac{2}{y^3}\right)dy | \begin{align} | ||
= y^4-y^-2\ | |||
= (1-1)-\left(16-\frac{1}{4}\right) | \int_{-2}^{-1}\left(4y^3+\frac{2}{y^3}\right)dy \\[2ex] | ||
= \frac{-63}{4} | &= \left[y^4-y^-2\right]_{-2}^{-1} \\[2ex] | ||
&= (1-1)-\left(16-\frac{1}{4}\right) \\[2ex] | |||
&= \frac{-63}{4} | |||
\end{align} | |||
</math> | </math> | ||
Revision as of 15:17, 21 September 2022
![{\displaystyle {\begin{aligned}\int _{-2}^{-1}\left(4y^{3}+{\frac {2}{y^{3}}}\right)dy\\[2ex]&=\left[y^{4}-y^{-}2\right]_{-2}^{-1}\\[2ex]&=(1-1)-\left(16-{\frac {1}{4}}\right)\\[2ex]&={\frac {-63}{4}}\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/12cdacd6670987149ea1ec3a315ffd91c229235c)