5.4 Indefinite Integrals and the Net Change Theorem/37: Difference between revisions

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\begin{align}
\begin{align}


& \int_{0}^{\frac{\pi}{4}}\left(\frac{1+\cos^2(\theta)}{\cos^2(\theta)}\right)d\theta \ = \ \int_{0}^{\frac{\pi}{4}}\frac{1}{\cos^2(\theta)} + \frac{\cos^2(\theta)}{\cos^2(\theta)} \ =    \ \int_{0}^{\frac{\pi}{4}} \frac{1}{\cos^2(\theta)} + 1 \\[2ex]
\int_{0}^{\frac{\pi}{4}}\left(\frac{1+\cos^2(\theta)}{\cos^2(\theta)}\right)d\theta &=
 
\int_{0}^{\frac{\pi}{4}}\frac{1}{\cos^2(\theta)} + \frac{\cos^2(\theta)}{\cos^2(\theta)} \\[2ex]
 
\int_{0}^{\frac{\pi}{4}} \frac{1}{\cos^2(\theta)} + 1 \\[2ex]


& =\tan({\theta}) + \theta \ \bigg|_{0}^{\frac{\pi}{4}}\\[2ex]
& =\tan({\theta}) + \theta \ \bigg|_{0}^{\frac{\pi}{4}}\\[2ex]

Revision as of 15:57, 21 September 2022