5.4 Indefinite Integrals and the Net Change Theorem/41: Difference between revisions
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&=\left[\arctan\left(\frac{1}{\sqrt{3}}\right)\right]-[\arctan(0)] \\[2ex] | &=\left[\arctan\left(\frac{1}{\sqrt{3}}\right)\right]-[\arctan(0)] \\[2ex] | ||
&=\frac{\pi}{6}-0=\frac{\pi}{6} | &=\frac{\pi}{6}-0 \\[2ex] | ||
&=\frac{\pi}{6} | |||
\end{align} | \end{align} | ||
</math> | </math> |
Revision as of 16:33, 21 September 2022