5.5 The Substitution Rule/13: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 6: | Line 6: | ||
\begin{align} | \begin{align} | ||
u &=5-3x | u &=5-3x \\[2ex] | ||
du &=-3dx | du &=-3dx \\[2ex] | ||
-\frac{1}{3}du &=dx | -\frac{1}{3}du &=dx | ||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 16:25, 22 September 2022
![{\displaystyle {\begin{aligned}u&=5-3x\\[2ex]du&=-3dx\\[2ex]-{\frac {1}{3}}du&=dx\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/084b592569fb6ffccbc984e9ef712892c68f0b7f)