6.1 Areas Between Curves/5: Difference between revisions

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<math>\int_{-1}^{2}[(9-x^{2}) - (x+1)] dx = [9x-\frac{x^{3}}{3}-\frac{x^{2}}{2}-x]\Bigg|_{-1}^{2} = [9(2)-\frac{(2)^{3}}{3}-\frac{(2)^{2}}{2}-(2)-(9(-1)-\frac{(-1)^{3}}{3}-\frac{(-1)^{2}}{2}-(-1))] = 18-\frac{8}{3}--2-2+9-\frac{1}{3}+\frac{1}{2}-1 = 19.5
<math>\int_{-1}^{2}[(9-x^{2}) - (x+1)] dx  
&= [9x-\frac{x^{3}}{3}-\frac{x^{2}}{2}-x]\Bigg|_{-1}^{2} = [9(2)-\frac{(2)^{3}}{3}-\frac{(2)^{2}}{2}-(2)-(9(-1)-\frac{(-1)^{3}}{3}-\frac{(-1)^{2}}{2}-(-1))]  
 
&= 18-\frac{8}{3}--2-2+9-\frac{1}{3}+\frac{1}{2}-1 = 19.5




</math>
</math>

Revision as of 19:12, 22 September 2022

Desmos-graph-5.png

Failed to parse (syntax error): {\displaystyle \int_{-1}^{2}[(9-x^{2}) - (x+1)] dx &= [9x-\frac{x^{3}}{3}-\frac{x^{2}}{2}-x]\Bigg|_{-1}^{2} = [9(2)-\frac{(2)^{3}}{3}-\frac{(2)^{2}}{2}-(2)-(9(-1)-\frac{(-1)^{3}}{3}-\frac{(-1)^{2}}{2}-(-1))] &= 18-\frac{8}{3}--2-2+9-\frac{1}{3}+\frac{1}{2}-1 = 19.5 }