5.3 The Fundamental Theorem of Calculus/8: Difference between revisions

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<math>g(x)=\int_{3}^{x}e^{t^2-t}dt</math><br>
<math>g(x)=\int_{3}^{x}e^{t^2-t}dt</math><br>
<math>\frac{d}{dx}\left[\int_{3}^{x}e^{t^2-t}dt\right]</math>
<math>\frac{d}{dx}\left[\int_{3}^{x}e^{t^2-t}dt\right]=1e^{x^2-x}-0e^{(0)^2-0}=e^{x^2-x}</math>

Revision as of 20:12, 23 August 2022