5.3 The Fundamental Theorem of Calculus/17: Difference between revisions

Revision as of 01:30, 24 August 2022

FTC #1 $y=\int \limits _{1-3x}^{1}{\frac {x^{3}}{(1+u^{2})}}dx$

$G(x)=f(x)$

so $y=\int \limits _{1-3x}^{1}{\frac {1}{(1+u^{2})}}x^{3},dx$

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	so		so
	<math>y=\int\limits_{1-3x}^{1}\frac{1}{(1+u^2)}*x^3, dx</math>		<math>y=\int\limits_{1-3x}^{1}\frac{1}{(1+u^2)}x^3, dx</math>