( 1 2 , − 3 2 ) {\displaystyle \left({\frac {1}{2}},-{\frac {\sqrt {3}}{2}}\right)}
sin ( t ) = − 3 2 cos ( t ) = 1 2 tan ( t ) = − 3 2 1 2 = − 3 2 {\displaystyle {\begin{aligned}\sin {(t)}&=-{\frac {\sqrt {3}}{2}}\\\cos {(t)}&={\frac {1}{2}}\\\tan {(t)}&={\frac {-{\frac {\sqrt {3}}{2}}}{\frac {1}{2}}}=-{\frac {\sqrt {3}}{2}}\\\end{aligned}}}
