− 5 π 4 ⋅ 180 ∘ π = 5 π ( 2 ) ( 2 ) ⋅ 2 π {\displaystyle {\frac {-5\pi }{4}}\cdot {\frac {180^{\circ }}{\pi }}={\frac {5{\cancel {\pi }}}{{\cancel {(2)}}{\cancel {(2)}}}}\cdot {\frac {\cancel {2}}{\cancel {\pi }}}}
