5.3 The Fundamental Theorem of Calculus/53

$\int _{2x}^{3x}{\frac {u^{2}-1}{u^{2}+1}}du$

${\frac {d}{dx}}\left[\int _{2x}^{3x}{\frac {u^{2}-1}{u^{2}+1}}du\right]=3*{\frac {1}{x^{2}}}$

<math>\left[(3)\frac{(3x)^2-1}{(3x)^2+1}du\right]