∫ − 1 0 ( 2 x − e x ) d x {\displaystyle \int _{-1}^{0}(2x-e^{x})dx}
= ∫ − 1 0 2 x d x − ∫ − 1 0 e x d x {\displaystyle =\int _{-1}^{0}2xdx-\int \limits _{-1}^{0}e^{x}dx}
= − 1 − ( 1 − 1 e ) = 1 e − 2 {\displaystyle =-1-(1-{\frac {1}{e}})={\frac {1}{e}}-2}
