y = 1 + x y = 3 + x 3 {\displaystyle {\begin{aligned}&\color {red}\mathbf {y=1+{\sqrt {x}}} &\color {royalblue}\mathbf {y={\frac {3+x}{3}}} \\\\\end{aligned}}}
1 + x = 3 + x 3 1 + x − 3 + x 3 = 0 x 2 = 4 x = ± 2 {\displaystyle {\begin{aligned}1+{\sqrt {x}}&={\frac {3+x}{3}}\\1+{\sqrt {x}}-{\frac {3+x}{3}}&=0\\x^{2}&=4\\x&=\pm 2\end{aligned}}}
