y = 1 + x y = 3 + x 3 {\displaystyle {\begin{aligned}&\color {red}\mathbf {y=1+{\sqrt {x}}} &\color {royalblue}\mathbf {y={\frac {3+x}{3}}} \\\\\end{aligned}}}
1 + x = 3 + x 3 = 1 + x − 3 + x 3 = 0 = 3 + 3 x 3 − 3 + x 3 = 0 = 3 + 3 x − 3 + x = 0 = 3 x + x = 0 = 3 x = − x = 9 x = x 2 = 9 x − x 2 = 0 = x ( 9 − x ) = 0 = x = 0 , 9 {\displaystyle {\begin{aligned}1+{\sqrt {x}}={\frac {3+x}{3}}\\[2ex]&=1+{\sqrt {x}}-{\frac {3+x}{3}}=0\\&={\frac {3+3{\sqrt {x}}}{3}}-{\frac {3+x}{3}}=0\\&=3+3{\sqrt {x}}-3+x=0\\&=3{\sqrt {x}}+x=0\\&=3{\sqrt {x}}=-x\\&=9x=x^{2}\\&=9x-x^{2}=0\\&=x(9-x)=0\\&=x=0,9\end{aligned}}}
![{\displaystyle {\begin{aligned}1+{\sqrt {x}}={\frac {3+x}{3}}\\[2ex]&=1+{\sqrt {x}}-{\frac {3+x}{3}}=0\\&={\frac {3+3{\sqrt {x}}}{3}}-{\frac {3+x}{3}}=0\\&=3+3{\sqrt {x}}-3+x=0\\&=3{\sqrt {x}}+x=0\\&=3{\sqrt {x}}=-x\\&=9x=x^{2}\\&=9x-x^{2}=0\\&=x(9-x)=0\\&=x=0,9\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/c1735f294b525957049215529c5757e3faefd4aa)
