y = x + 1 y = 9 − x 2 x = − 1 x = 2 {\displaystyle {\begin{aligned}&\color {red}\mathbf {y=x+1} &\color {royalblue}\mathbf {y=9-x^{2}} \\&x=-1&x=2\\\end{aligned}}}
∫ − 1 2 | ( 9 − x 2 ) − ( x + 1 ) | d x {\displaystyle \int _{-1}^{2}\left|(9-x^{2})-(x+1)\right|dx}