5.5 The Substitution Rule/13

$\int {\frac {dx}{5-3x}}{\text{,}}\quad u=5-3x$

${\begin{aligned}u&=5-3x\\[2ex]du&=-3dx\\[2ex]-{\frac {1}{3}}du&=dx\end{aligned}}$

Failed to parse (unknown function "\x"): {\displaystyle \begin{align} \int \frac{dx}{5-3x} &= -\frac{1}{3}\int \left(\frac{1}{u}\right)du \\[2ex] &=-\frac{1}{3}\ln{(\x)} du \end{align} }