∫ 0 1 x 2 ( 1 + 2 x 3 ) 5 d r {\displaystyle \int _{0}^{1}x^{2}(1+2x^{3})^{5}dr}
u = 1 + 2 x 3 {\displaystyle {\begin{aligned}u&=1+2x^{3}\\[2ex]\end{aligned}}}
d u = 6 x 2 d x {\displaystyle {\begin{aligned}du&=6x^{2}dx\\[2ex]\end{aligned}}}
∫ 1 3 u 5 {\displaystyle {\begin{aligned}\int _{1}^{3}u^{5}\\[2ex]\end{aligned}}}
![{\displaystyle {\begin{aligned}u&=1+2x^{3}\\[2ex]\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/bb7af9540f66d41bbcd61431c87e360f7975b4a3)
![{\displaystyle {\begin{aligned}du&=6x^{2}dx\\[2ex]\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/62e39f21f3ca2c85aa04408ea0ace6e63450da2b)
![{\displaystyle {\begin{aligned}\int _{1}^{3}u^{5}\\[2ex]\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/f2d24715e03c6d41b27f9378db200a6c4848add4)