∫ x 2 x 3 + 1 d x {\displaystyle \int x^{2}{\sqrt {x^{3}+1}}dx}
u = x 3 + 1 {\displaystyle {\begin{aligned}u=x^{3}+1\\[2ex]\end{aligned}}}
∫ 1 3 d u u {\displaystyle \int {\frac {1}{3}}du{\sqrt {u}}}
![{\displaystyle {\begin{aligned}u=x^{3}+1\\[2ex]\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/7cf9dc09ffa0ee33217ede3dac13519f072ca01a)
