∫ 0 1 ( 3 + x x ) d x = ∫ 0 1 ( 3 + x 1 + 1 2 ) d x {\displaystyle \int _{0}^{1}\left(3+x{\sqrt {x}}\right)dx=\int _{0}^{1}\left(3+x^{1+{\frac {1}{2}}}\right)dx}