5.3 The Fundamental Theorem of Calculus/33

$h(x)=\int _{2}^{1/x}\arctan(t)dt$

Failed to parse (unknown function "\math"): {\displaystyle \frac{d}{dx}\left[h(x)\right]=\frac{d}{dx}\left[\int_{2}^{1/x}\arctan(t)dt\right] <\math>\frac{-1}{x^2}\left(\arctan(\frac{1}{x}\right)-0}