π 12 = π 2 ⋅ 6 ⋅ 180 ∘ π = 2 ⋅ 3 ⋅ 5 1 ⋅ π 2 ⋅ 2 ⋅ 5 ⋅ 3 ⋅ 3 = π 6 {\displaystyle {\frac {\pi }{12}}={\frac {\pi }{2\cdot 6}}\cdot {\frac {180^{\circ }}{\pi }}={\frac {{\cancel {2}}\cdot {\cancel {3}}\cdot {\cancel {5}}}{1}}\cdot {\frac {\pi }{{\cancel {2}}\cdot {2}\cdot {\cancel {5}}\cdot {\cancel {3}}\cdot 3}}={\frac {\pi }{6}}}
