∫ 2 x 3 x u 2 − 1 u 2 + 1 d u {\displaystyle \int _{2x}^{3x}{\frac {u^{2}-1}{u^{2}+1}}du}
d d x [ ∫ 2 x 3 x u 2 − 1 u 2 + 1 d u ] = ( 3 ∗ 3 x 2 − 1 3 x 2 + 1 ) {\displaystyle {\frac {d}{dx}}\left[\int _{2x}^{3x}{\frac {u^{2}-1}{u^{2}+1}}du\right]=(3*{\frac {3x^{2}-1}{3x^{2}+1}})}
![{\displaystyle {\frac {d}{dx}}\left[\int _{2x}^{3x}{\frac {u^{2}-1}{u^{2}+1}}du\right]=(3*{\frac {3x^{2}-1}{3x^{2}+1}})}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/602b414af3b3f948d46438f111f8c8bbaa8276fb)