∫ 1 2 ( 1 + 2 y 2 ) d y {\displaystyle \int _{1}^{2}\left(1+2y^{2}\right)dy} = ∫ 1 2 ( 4 y 2 + 4 y + 1 ) d y {\displaystyle \int _{1}^{2}\left(4y^{2}+4y+1\right)dy} = 4 y 3 3 + f r a c 4 y 2 2 {\displaystyle {\frac {4y^{3}}{3}}+frac{4y^{2}}{2}}
