∫ 0 2 ( x − 1 ) 25 d x ∫ t 25 d t t 25 26 {\displaystyle {\begin{aligned}&\int _{0}^{2}({x-1})^{25}dx\\[2ex]&\int {t^{25}}dt\\[2ex]&{\cfrac {t^{25}}{26}}\end{aligned}}}