5.5 The Substitution Rule/7

$\int x\sin {(x^{2})}dx$

${\begin{aligned}u&=x^{2}\\[2ex]du&=2xdx\\[2ex]{\frac {1}{2}}du&=dx\\[2ex]\end{aligned}}$

Failed to parse (unknown function "\intxsin"): {\displaystyle \begin{align} \intxsin{(x^{2})}dx &=\frac{1}{2}\int\sin{(u)}du \\[2ex] &= -\frac{1}{2}cos{(u)}+C \\[2ex] &= -\frac{1}{2}cos{(x^{2})}+C \end{align} }