y = 12 − x 2 {\displaystyle \color {red}{y=12-x^{2}}}
y = x 2 − 6 {\displaystyle \color {blue}{y=x^{2}-6}}
∫ 3 − 3 | ( 12 − x 2 ) − ( x 2 − 6 ) | d x {\displaystyle \int _{3}^{-3}\left|(12-x^{2})-(x^{2}-6)\right|dx}
