y = x + 1 y = 9 − x 2 x = − 1 x = 2 {\displaystyle {\begin{aligned}&\color {red}\mathbf {y=x+1} &\color {royalblue}\mathbf {y=9-x^{2}} \\&x=-1&x=2\\\end{aligned}}}
∫ − 1 2 ( ( 9 − x 2 ) − ( x + 1 ) ) d x = 9 x − x 3 3 − x 2 2 | − 1 2 {\displaystyle \int _{-1}^{2}((9-x^{2})-(x+1))dx=9x-{\frac {x^{3}}{3}}-{\frac {x^{2}}{2}}{\Bigg |}_{-1}^{2}}
