∫ 0 1 x 2 ( 1 + 2 x 3 ) 5 d r u = 1 + 2 x 3 < m a t h > d u 6 {\displaystyle \int _{0}^{1}x^{2}(1+2x^{3})^{5}dru=1+2x^{3}<math>{\frac {du}{6}}} </math>
