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• 09:16, 7 September 2022 Rubyp61202@students.laalliance.org talk contribs created page 5.5 The Substitution Rule/65 (Created page with "<math> \int_{1}^{2} x \sqrt{x-1} dx = \int_{0}^{1} u+1 \sqrt{u}du = \int_{0}^{1}(u + 1)(\sqrt{u}) = \int_{0}^{1} u^ \frac{2}{3} + \sqrt{u}du = \frac{2}{5} + \frac{2}{3} = \frac{16}{15} </math>")