5.3 The Fundamental Theorem of Calculus/9

Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align} g(y)&= \int_{y}^{2}t^2\sin{(t)}dt \\[2ex] &= 1(y^{2}sin{(y)})-0(2^{2}sin{(2)})\\[2ex] &= y^{2} sin{(y)} \\[2ex] \end(align)}