∫ 0 1 x 4 5 d x = 5 x 4 5 ∗ 9 = 5 x 4 5 ∗ 9 | 0 1 {\displaystyle {\begin{aligned}&\int _{0}^{1}x^{\cfrac {4}{5}}dx\\[2ex]&={\cfrac {5{\sqrt[{5}]{x^{4}}}}{*}}{9}\\[2ex]&={\cfrac {5{\sqrt[{5}]{x^{4}}}}{*}}{9}{\bigg |}_{0}^{1}\end{aligned}}}